## E0109: for-of loop expression cannot have semicolons

There are three kinds of `for` loops: C-style `for` loops (`;`), `for`-`in` loops, and `for`-`of` loops. It is a syntax error to write a `for`-`of` loop with a `;`:

    for (let i of 0; i < 100; ++i) {
      console.log(i % 15 ? i : "FizzBuzz");
    }

    for (const benchmark of collectBenchmarks();) {
      runBenchmark(benchmark);
    }

To fix this error, remove the `of` keyword in the C-style `for` loop:

    for (let i = 0; i < 100; ++i) {
      console.log(i % 15 ? i : "FizzBuzz");
    }

Alternatively, remove the extra `;`:

    for (const benchmark of collectBenchmarks()) {
      runBenchmark(benchmark);
    }

Documentation for other errors