## E0124: cannot declare variable named keyword

It is a syntax error to declare a variable named certain keywords like `debugger` or `while`:

    function parseVar(s) {
      let var = s.split()[0];
      let value = s.split()[1];
      return {var, value};
    }

To fix this error, pick a different variable name:

    function parseVar(s) {
      let varName = s.split()[0];
      let value = s.split()[1];
      return {varName, value};
    }

Documentation for other errors