E0718: using a '.' after a '?.' might fail, since '?.' might return 'undefined'
In JavaScript, x?.y ignores y and returns undefined if x is null or undefined. If ?. returns undefined, then using . after will throw an error:
let bug = { milestone: null };
console.log(bug.milestone); // null
console.log(bug.milestone?.name); // undefined
console.log(bug.milestone?.name.trim()); // throws an error
Replacing the . with ?. will prevent the errors from being thrown at runtime:
let bug = { milestone: null };
console.log(bug.milestone?.name?.trim()); // undefined